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How does eval overhere or how does it behave?
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How does eval overhere or how does it behave?
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eval(0+'1'+3) => 11 (???)
When eval(0+'1') is executed =>1. Iam expecting that 0+'1' will give me 1 & 3 will be considered as string & o/p => 13. But, why is that not happening?
whereas
eval(1+'1'+3) => 113
You are creating the string "013", which is evaluated as a JavaScript integer literal. Integer literals starting with 0 are interpreted base 8 (octal), so your number is 8 + 3, which is 11.
Only integer literals starting with a non-zero digit are interpreted base 10.
Tags
javascript
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