PROBLEM OF THE DAY : 21/02/2024 | Boolean Parenthesization
source link: https://www.geeksforgeeks.org/videos/problem-of-the-day-21022024-boolean-parenthesization/
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PROBLEM OF THE DAY : 21/02/2024
Welcome to the daily solving of our PROBLEM OF THE DAY with Yash Dwivedi. We will discuss the entire problem step-by-step and work towards developing an optimized solution. This will not only help you brush up on your concepts of Strings but also build up problem-solving skills.
In this problem, we are given a boolean expression s of length n with following symbols.
Symbols
'T' ---> true
'F' ---> false
and following operators filled between symbols
Operators
& ---> boolean AND
| ---> boolean OR
^ ---> boolean XOR
Count the number of ways we can parenthesize the expression so that the value of expression evaluates to true.
Note: The answer can be large, so return it with modulo 1003
Example :
Input:
n = 7
s = T|T&F^T
Output:
4
Explaination:
The expression evaluates to true in 4 ways ((T|T)&(F^T)), (T|(T&(F^T))), (((T|T)&F)^T) and (T|((T&F)^T)).
Give the problem a try before going through the video. All the best!!!
Problem Link: https://www.geeksforgeeks.org/problems/boolean-parenthesization5610/1
Solution IDE Link: https://ide.geeksforgeeks.org/online-cpp14-compiler/f95d2a26-8452-4572-b9f2-791e83eba7cf
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