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ConstParamTy: require Eq as supertrait by RalfJung · Pull Request #116125 · rust...

 11 months ago
source link: https://github.com/rust-lang/rust/pull/116125
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require Eq as supertrait by RalfJung · Pull Request #116125 · rust-lang/rust · GitHub

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As discussed with @BoxyUwU on Zulip.

We want to say that valtree equality on const generic params agrees with ==, but that only makes sense if == actually exists, hence we should have an appropriate bound. Valtree equality is an equivalence relation, so such a type can always be Eq and not just PartialEq.

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added S-waiting-on-review Status: Awaiting review from the assignee but also interested parties. T-compiler Relevant to the compiler team, which will review and decide on the PR/issue. T-libs Relevant to the library team, which will review and decide on the PR/issue.

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Sep 24, 2023

@@ -986,11 +986,16 @@ pub trait Tuple {}

pub trait PointerLike {}

/// A marker for types which can be used as types of `const` generic parameters.

///

/// These types must have a proper equivalence relation (`Eq`) and it must be automatically

Is this "just in case"? Like, there are no types that implement StructuralEq that don't also implement Eq, right, at least without a manual StructuralEq impl?

Would be nice if you could add a test showing where possibly dubious code goes from pass -> err.

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Like, there are no types that implement StructuralEq that don't also implement Eq, right, at least without a manual StructuralEq impl?

Not quite.
A generic type with derive(Eq) will implement StructuralEq without any bounds on the generic parameters.

Is this "just in case"?

This is mostly to make the 2nd half of the comment coherent: we want to say that valtree equality agrees with ==. Without at least a PartialEq bound, that statement is ill-formed, since the type might not even have ==.

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Would be nice if you could add a test showing where possibly dubious code goes from pass -> err.

I don't know any such test (without a manual StructualEq impl), but currently the invariants that achieve that ConstParamTy implies Eq are rather subtle. This makes them a lot more obvious.

currently the invariants that achieve that ConstParamTy implies Eq are rather subtle. This makes them a lot more obvious.

Yeah, ok, that's all I wanted to really know. This isn't necessarily for "correctness" (but perhaps only by accident do we imply the right thing due to recursively checking fields for ConstParamTy in impls).

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I also view this as preparation for removing the StructuralEq trait entirely (at which point only the StructuralPartialEq bound would be left otherwise).

I can do that all in the same PR if you prefer.

compiler-errors reacted with thumbs up emoji

Nah, I'll probably have more questions about behavioral changes on that PR anyways 😅


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