PROBLEM OF THE DAY: 15/08/2023 | Flip Bits
source link: https://www.geeksforgeeks.org/videos/problem-of-the-day-15082023-flip-bits/
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PROBLEM OF THE DAY: 15/08/2023
Welcome to the daily solving of our PROBLEM OF THE DAY with Karan Mashru. We will discuss the entire problem step-by-step and work towards developing an optimized solution. This will not only help you brush up on your concepts of Bit Manipulation but will also help you build up problem-solving skills.
In this video, we are given an array A[] consisting of 0’s and 1’s. A flip operation is one in which you turn 1 into 0 and a 0 into 1. We have to do at most one “Flip” operation of any subarray. Formally, select a range (l, r) in the array A[], such that (0 ≤ l ≤ r < n) holds and flip the elements in this range to get the maximum ones in the final array. You can possibly make zero operations to get the answer.
Example :
Input:
N = 5
A[] = {1, 0, 0, 1, 0}
Output:
4
Explanation:
We can perform a flip operation in the range [1,2]
After the flip operation array is : [ 1 1 1 1 0 ]
The count of one after fliping is: 4
[Note: the subarray marked in bold is the flipped subarray]
Give the problem a try before going through the video. All the best!!!
Problem Link: https://practice.geeksforgeeks.org/problems/flip-bits0240/1
Solution IDE Link: https://ide.geeksforgeeks.org/online-cpp14-compiler/18039f00-72e6-4890-bd12-e004ae05667f
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