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使用共享引用说明Rust所有权概念
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使用共享引用说明Rust所有权概念
共享引用（&T）是复制Copy特性（见这里，值复制）。
下面是一个常用类型的例子，字符串slice片&str。
下面我们可以在第3行和第4行将name传递给do_something。注意，我们正在复制引用。
fn main() {
let name: &'static str = "Rust";
do_something(name);
do_something(name);
}
fn do_something(name: &str) {
println!("Hello, {:?}!", name);
}
|
输出：
Hello, Rust! Hello, Rust! |
下面代码在把name传给do_something之前调用.clone()是多余的。
fn main() {
let name: &'static str = "Rust";
do_something(name.clone());
do_something(name.clone());
}
fn do_something(name: &str) {
println!("Hello, {:?}!", name);
}
|
根据Clippy的建议，<&str>::clone(&name)这个习惯语会克隆引用。该程序可以编译，但我不确定这是否是习惯用法。
fn main() {
let name: &'static str = "Rust";
do_something(<&str>::clone(&name));
do_something(<&str>::clone(&name));
}
fn do_something(name: &str) {
println!("Hello, {:?}!", name);
}
|
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