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#yyds干货盘点# leetcode算法题：最后一个单词的长度
source link: https://blog.51cto.com/u_13321676/5488218
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#yyds干货盘点# leetcode算法题：最后一个单词的长度
原创给你一个字符串 s，由若干单词组成，单词前后用一些空格字符隔开。返回字符串中 最后一个 单词的长度。
单词 是指仅由字母组成、不包含任何空格字符的最大子字符串。
输入：s = "Hello World"
解释：最后一个单词是“World”，长度为5。
输入：s = " fly me to the moon "
解释：最后一个单词是“moon”，长度为4。
输入：s = "luffy is still joyboy"
解释：最后一个单词是长度为6的“joyboy”。
代码实现：
class Solution {
public int lengthOfLastWord(String s) {
int index = s.length() - 1;
while (s.charAt(index) == ' ') {
index--;
}
int wordLength = 0;
while (index >= 0 && s.charAt(index) != ' ') {
wordLength++;
index--;
}
return wordLength;
}
}
public int lengthOfLastWord(String s) {
int index = s.length() - 1;
while (s.charAt(index) == ' ') {
index--;
}
int wordLength = 0;
while (index >= 0 && s.charAt(index) != ' ') {
wordLength++;
index--;
}
return wordLength;
}
}
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