4

Luogu P4412. [SHOI2004]最小生成树

 1 year ago
source link: https://www.shuizilong.com/house/archives/luogu-p4412-shoi2004%e6%9c%80%e5%b0%8f%e7%94%9f%e6%88%90%e6%a0%91/
Go to the source link to view the article. You can view the picture content, updated content and better typesetting reading experience. If the link is broken, please click the button below to view the snapshot at that time.
July 5, 2022

这个题主要麻烦的点还是找环。。。

const int N = 50 + 9, M = int(1.5e3) + 9;
struct Graph {
int id[N][N];
struct edge {
int x, y, w;
void in() {
RD(x, y, w);
}
} E[M];
int n, m;
void in() {
RD(n, m); REP_1(i, m) {
E[i].in();
id[E[i].x][E[i].y] = id[E[i].y][E[i].x] = i;
}
}
} G;
struct Tree {
VI adj[N]; int fa[N], dep[N];
void dfs(int u = 1, int p = -1) {
for (auto v: adj[u]) if (v != p) {
fa[v] = u; dep[v] = dep[u] + 1;
dfs(v, u);
}
}
void in() {
DO(G.n-1) {
int x, y; RD(x, y);
adj[x].PB(y);
adj[y].PB(x);
}
dfs();
}
} T;
struct Simplex {
const static int N = ::M, M = int(1e3) + 9;
DB a[N+1][M+1];
int n, m;
void pivot(int in, int out) {
REP(i, m+1) if(i!=in) a[out][i] /= -a[out][in]; //重置out约束
a[out][in] = 1/a[out][in];
REP(i, n+1) if (i!=out && sgn(a[i][in])) { //重新计算其他约束
DB t = a[i][in]; a[i][in] = 0;
REP(j, m+1) a[i][j] += t*a[out][j];
}
}
DB run() {
while (true) {
int in=0, out=0; DB Min=OO;
REP_1(i, m) if(sgn(a[0][i])>0) {
in=i;
break;
}
if(!in)return a[0][0];
REP_1(i, n) if(sgn(a[i][in])<0&&a[i][0]/-a[i][in]<Min) {
Min=a[i][0]/-a[i][in];
out=i;
}
if(!out)throw; //unbounded
pivot(in, out);
}
}
int gao() {
// z b
// c A
G.in(); T.in();
n = G.m; m = 0; REP_1(i, n) {
a[i][0] = 1;
int u = G.E[i].x, v = G.E[i].y;
if (T.dep[u] < T.dep[v]) swap(u, v);
if (T.fa[u] != v) { // E[i] is not a tree edge
while (u != v) {
int p = T.fa[u];
int j = G.id[p][u]; // E[j] is a tree edge
if (G.E[i].w < G.E[j].w) {
++m; a[i][m] = a[j][m] = -1;
a[0][m] = G.E[j].w - G.E[i].w;
}
u = p; if (T.dep[u] < T.dep[v]) swap(u, v);
}
}
}
return run();
}
} fst;
int main() {
#ifndef ONLINE_JUDGE
freopen("in.txt", "r", stdin);
//freopen("out.txt", "w", stdout);
#endif
OT(fst.gao());
}

Posted by xiaodao
Category: 日常


About Joyk


Aggregate valuable and interesting links.
Joyk means Joy of geeK