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【leetcode】7.整数反转
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【leetcode】7.整数反转
2018-12-05
5
给出一个 32 位的有符号整数，你需要将这个整数中每位上的数字进行反转。
示例 1:
输入: 123
输出: 321
示例 2:
输入: -123
输出: -321
示例 3:
输入: 120
输出: 21
注意:
假设我们的环境只能存储得下 32 位的有符号整数，则其数值范围为 [−231231, 231231, − 1]。请根据这个假设，如果反转后整数溢出那么就返回 0。
python
class Solution(object):
def reverse(self, x):
"""
:type x: int
:rtype: int
"""
x = list(str(x))
if x[0] == '-':
x = (-1)*int(''.join(x[-1:-len(x):-1]))
else:
x = int(''.join(x[::-1]))
if x>= (-1)*(2**31) and x<=2**31:
return x
else:
return 0
参考资料：
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