7
Python 列表踢出某个元素上机作业题
source link: https://www.v2ex.com/t/821251
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请根据输入的原始列表，输出目标列表：
原始列表：[1,2,None,None,None,None,None,None,3,4,5,6,None,None,None,None,7,8,9,10]
目标列表： [1,2] [3,4,5,6] [7,8,9,10]
12 条回复 • 2021-12-10 15:43:42 +08:00
princelai 6 小时 30 分钟前 
1
from itertools import groupby
[list(g[1]) for g in groupby(ll,key=lambda x:x is not None) if g[0]]
[list(g[1]) for g in groupby(ll,key=lambda x:x is not None) if g[0]]
JasonEWNL 2 小时 52 分钟前
@deplivesb 高级点，Way to Overflow 。（
@going 话说回来鉴于是作业，或可回归不依赖任何库的一般思路，日后有机会亦能写出不一定最具效率但较易维护的代码。
```
il = [1, 2, None, None, None, None, None, None, 3, 4, 5, 6, None, None, None, None, 7, 8, 9, 10]
ol = [[]]
for i in il:
if i:
ol[-1].append(i)
elif ol[-1]:
ol.append([])
print(ol) # [[1, 2], [3, 4, 5, 6], [7, 8, 9, 10]]
```
@going 话说回来鉴于是作业，或可回归不依赖任何库的一般思路，日后有机会亦能写出不一定最具效率但较易维护的代码。
```
il = [1, 2, None, None, None, None, None, None, 3, 4, 5, 6, None, None, None, None, 7, 8, 9, 10]
ol = [[]]
for i in il:
if i:
ol[-1].append(i)
elif ol[-1]:
ol.append([])
print(ol) # [[1, 2], [3, 4, 5, 6], [7, 8, 9, 10]]
```
fml87 1 小时 10 分钟前
lst = [1,2,None,None,None,None,None,None,3,4,5,6,None,None,None,None,7,8,9,10]
[*map(eval,re.split(",,+",re.sub("[^0-9,]", "",str(lst) )))]
[*map(eval,re.split(",,+",re.sub("[^0-9,]", "",str(lst) )))]
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