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Parse error: syntax error, unexpected end of file in C:\xampp\htdocs\clinica\val...
source link: https://www.codeproject.com/Questions/5318145/Parse-error-syntax-error-unexpected-end-of-file-in
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Hi everyone! I have a problem in My system when I send My data to My database, and I do not know why it happens, by the way my queries I have to change them to parameterized (THE ERROR IS IN MY QUESTION 😉)
This is my code(THE ERROR IT´S IN THE LAST LINE):
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<?php include ("conex.php"); //logeo session_start(); include("conex.php"); if(isset($_POST['ingre'])){ $name = $_POST["name"]; $password = $_POST["pass"]; $sql = "SELECT COUNT(*) as contar FROM usuario WHERE name ='$name' AND pass ='$password'"; $consult=mysqli_query($conn,$sql); $arreglo=mysqli_fetch_array($consult); if($arreglo['contar']> 0) { $_SESSION['usuario']=$name; echo "<script>alert('Bienvenido: $name'); window.location='home.php'</script>"; }else{ echo "<script>alert('Los datos estan mal'); window.location='login.php'</script>"; } //Registrar $name = $_POST["name"]; $apellido = $_POST["apec"]; $dad = $_POST["namep"]; $mom = $_POST["namem"]; $tipeCI = $_POST["tipeid"]; $ci = $_POST["ci"]; $phone = $_POST["te"]; $correo = $_POST["email"]; $add = $_POST["dirre"]; $day = $_POST["diana"]; $gradoI = $_POST["gradoin"]; $esC = $_POST["estado"]; $sex = $_POST["sex"]; $pass = $_POST["pass"]; if(isset($_POST["butt"])) { $sqlgrabar = "INSERT INTO usuario(name,last,nameDad,nameMom,tipoIdentificacion,identificacion,telefono,email,address ,born,rango,estadoC,sex,pass) values ('$name','$apellido','$dad','$mom','$tipeCI','$ci','$phone','$correo','$add','$day','$gradoI','$esC', '$sex','$pass')"; //EVITAR REPETIDO $veri_correo=mysqli_query($conn,"SELECT * FROM usuario WHERE email='$correo'"); $veri_pass=mysqli_query($conn,"SELECT * FROM usuario WHERE pass='$pass'"); if(mysqli_num_rows($veri_correo) > 0){ echo '<script>window.location="dise/errorEgistro.php";</script>'; exit(); } if(mysqli_num_rows($veri_pass) > 0){ echo '<script>window.location="dise/errorEgistro.php";</script>'; exit(); } if(mysqli_query($conn,$sqlgrabar)) { echo "<script> alert('Felicidades el usuario fue registrado con exito: $name'); window.location='login.php' </script>"; }else { echo "Error: ".$sqlgrabar."<br>".mysqli_error($conn); } } ?>
What I have tried:
I tried some thing but nothing, I Am a little NOOB, and I don't why the error happened
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