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Create a Unix shell script with 4 parameters

 2 years ago
source link: https://www.codesd.com/item/create-a-unix-shell-script-with-4-parameters.html
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Create a Unix shell script with 4 parameters

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I have a file (for example system.log). I need to scan this file to find a specific string that must appear several times during a period of 5 minutes.

I imagine that I can make a script with 4 parameters:

  • the location of the file
  • the string to search
  • the number of times that the string appears
  • the period of time

If this script finds the string in the specified period of time it writes, for example, the message 'success'

Here's the begin of the script

#!/bin/ksh
#set -x

#############
# VARIABLES #
#############

location="/moteurs/websphere/7.0/esb/managed01/logs/"
file="SystemOut.log"
pattern="WSV0605W: Thread \"SIBFAPInboundThreadPool"
string=$(grep -ic "${pattern}" ${location}/${file})

Now that I've defined my variables, I don't know how can I make a function that scans SystemOut.log every 5 minutes.

Do you kown how can I create this shell?

Yes. Use your favorite editor, write the shell script, execute it. You are done.


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