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Why is not the boost :: shared_ptr - & gt; The operator is declared online?

 2 years ago
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Why is not the boost :: shared_ptr - & gt; The operator is declared online?

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Since boost::shared_ptr could be called very frequently and simply returns a pointer, isn't the -> operator a good candidate for being inlined?

T * operator-> () const // never throws
{
    BOOST_ASSERT(px != 0);
    return px;
}

Would a good compiler automatically inline this anyway?

Should I lose any sleep over this? :-)


Functions defined (i.e. with a body) inside a class are implicitly candidates for inlining. There is no need to use the inline keyword in these cases, and it is unusual to do so.

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