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Python 正则的问题 - V2EX
source link: https://www.v2ex.com/t/801288
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环境：py3.9.6
部分代码：
ip = '1.2.3.4:8080/3xx3/a.php?b=1'
parse_obj = urlparse(ip)
print(parse_obj)
解析之后的结果：
ParseResult(scheme='1.2.3.4', netloc='', path='8080/3xx3/a.php', params='', query='b=1', fragment='')
请问各位大佬，针对这种不带 http(s)://的情况，如何使用正则提取 path 中的端口而不要之后路径呢，小白求解。
部分代码：
ip = '1.2.3.4:8080/3xx3/a.php?b=1'
parse_obj = urlparse(ip)
print(parse_obj)
解析之后的结果：
ParseResult(scheme='1.2.3.4', netloc='', path='8080/3xx3/a.php', params='', query='b=1', fragment='')
请问各位大佬，针对这种不带 http(s)://的情况，如何使用正则提取 path 中的端口而不要之后路径呢，小白求解。
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