Increment odd positioned elements by 1 and decrement even positioned elements by...
source link: https://www.geeksforgeeks.org/increment-odd-positioned-elements-by-1-and-decrement-even-positioned-elements-by-1-in-an-array/
Go to the source link to view the article. You can view the picture content, updated content and better typesetting reading experience. If the link is broken, please click the button below to view the snapshot at that time.
Increment odd positioned elements by 1 and decrement even positioned elements by 1 in an Array
- Difficulty Level : Easy
- Last Updated : 26 Apr, 2021
Given an array arr[], the task is increment all the odd positioned elements by 1 and decrement all the even positioned elements by 1.
Examples:
Input: arr[] = {3, 6, 8}
Output: 4 5 9
Input: arr[] = {9, 7, 3}
Output: 10 6 4
Approach: Traverse the array element by element and if the current element’s position is odd then increment it by 1 else decrement it by 1. Prin the contents of the updated array in the end.
Below is the implementation of the above approach:
- Python3
- Javascript
// C++ implementation of the approach#include <bits/stdc++.h>using namespace std;// Utility function to print// the contents of an arrayvoid printArr(int arr[], int n){for (int i = 0; i < n; i++)cout << arr[i] << " ";}// Function to increment all the odd// positioned elements by 1 and decrement// all the even positioned elements by 1void updateArr(int arr[], int n){for (int i = 0; i < n; i++)// If current element is odd positionedif ((i + 1) % 2 == 1)arr[i]++;// If even positionedelsearr[i]--;// Print the updated arrayprintArr(arr, n);}// Driver codeint main(){int arr[] = { 3, 6, 8 };int n = sizeof(arr) / sizeof(arr[0]);updateArr(arr, n);return 0;}4 5 9
Time Complexity: O(n)
Auxiliary Space: O(1)
Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready. To complete your preparation from learning a language to DS Algo and many more, please refer Complete Interview Preparation Course.
In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.
Recommend
About Joyk
Aggregate valuable and interesting links.
Joyk means Joy of geeK