If a statement inside it depends on the same variable as if it depends on
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If a statement inside it depends on the same variable as if it depends on
consider the below programs. I would like to know why this codes behave in different way.Thankyou in advance.
this doesnot print any
#include <stdio.h>
int main() {
int i = 0;
while(i < 10) {
if(i < 7)
printf("value is%d", i++);
}
}
while this does
#include <stdio.h>
int main() {
int i = 0;
while(i < 10) {
if(i < 7)
printf("value is%d\n", i++);
}
}
First note both your programs never exit. When i hits 7 it's game over and your stuck forever doing nothing.
Second note the only difference is printing a new line. That should have been your clue. Since the loop is infinite you never print a new line or exit - both things flush STDOUT. Until you flush STDOUT you're just accumulating what you're trying to print in a buffer. Only the flushing will get it on screen, and clean the buffer.
@chux added a good point:
Buffering of STDOUT (or IN or ERR) is implementation defined, meaning different flavors of Linux, Windows, and so forth may display different behavior. Obviously in the OP STDOUT is buffered - as no output appears.
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