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喝饮料问题，饮料价格1元/瓶，两瓶饮料空瓶可以重新兑换一瓶饮料，问20元可以喝多少瓶...

 3 years ago
source link: https://segmentfault.com/a/1190000040426248
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喝饮料问题，饮料价格1元/瓶，两瓶饮料空瓶可以重新兑换一瓶饮料，问20元可以喝多少瓶饮料

发布于 7 分钟前
int main()//方法一
{
    int money = 0;//手上的钱，即用钱买回来的汽水数量
    int total = 0;//买的+兑的
    int empty = 0;//手里的空瓶
    scanf_s("%d", &money);
    int sum = totalsum(money);
    printf("sum=%d\n", sum);
    total = money;//用钱买回来的汽水数量
    empty = money;//喝完用钱买的汽水后手里的空瓶数量
    while (empty>=2)//只要空瓶不低于两瓶就可以换汽水
    {
        total += empty / 2;
        empty = empty / 2 + empty % 2;//空瓶的数量为换回来的空瓶+手里余下的空瓶
    }
    printf("total=%d\n", total);
}

方法2，因为两个空瓶换一瓶饮料，一瓶饮料1块钱，相当于1个空瓶等于0.5元，20块钱可以换40个空瓶，相当于喝了40瓶汽水，但因为最后手里留了一个空瓶，所以只能换来39个空瓶，即喝了39瓶汽水
int totalsum(int money)
{
    int sum = 0;
    if (money== 0)//手里没钱就不能喝饮料
    {
        return 0;
    }
    else
    {
        sum = money * 2 - 1;
        return sum;
    }
    
//}

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