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[IT 邦帮忙] 优化或重写方法，使计算长字符串时尽可能缩短运算时间
source link: https://www.v2ex.com/t/788339
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如果 str1 包含 str2 的所有字母（包括数量），为真，反之为假
function scramble(str1, str2) {
let s1 = str1.split("").sort()
let s2 = str2.split("").sort()
let n = 0
s2.forEach(e=>{
let index = s1.indexOf(e)
if(index>-1){
n++
s1.splice(index,1)
}
})
if(n==s2.length && n!=0){
return true
}else{
return false
}
}
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